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1.5x^2-3.2=0
a = 1.5; b = 0; c = -3.2;
Δ = b2-4ac
Δ = 02-4·1.5·(-3.2)
Δ = 19.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{19.2}}{2*1.5}=\frac{0-\sqrt{19.2}}{3} =-\frac{\sqrt{}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{19.2}}{2*1.5}=\frac{0+\sqrt{19.2}}{3} =\frac{\sqrt{}}{3} $
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